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Handle HTTPException when attempting to get ssh_info
The call to `urlopen` can raise `HTTPException`, but this is not caught which results in a python Traceback. Add handling of the exception. Because `HTTPException` and its derived classes do not have any message, print the name of the exception in the error message instead. Change-Id: Ic90fb4cc0e92702375cd976d4a03876c8ce8bffc
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@ -40,6 +40,10 @@ else:
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from signal import SIGTERM
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from signal import SIGTERM
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from error import GitError, UploadError
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from error import GitError, UploadError
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from trace import Trace
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from trace import Trace
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if is_python3():
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from http.client import HTTPException
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else:
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from httplib import HTTPException
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from git_command import GitCommand
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from git_command import GitCommand
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from git_command import ssh_sock
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from git_command import ssh_sock
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@ -608,6 +612,8 @@ class Remote(object):
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raise UploadError('%s: %s' % (self.review, str(e)))
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raise UploadError('%s: %s' % (self.review, str(e)))
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except urllib.error.URLError as e:
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except urllib.error.URLError as e:
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raise UploadError('%s: %s' % (self.review, str(e)))
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raise UploadError('%s: %s' % (self.review, str(e)))
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except HTTPException as e:
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raise UploadError('%s: %s' % (self.review, e.__class__.__name__))
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REVIEW_CACHE[u] = self._review_url
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REVIEW_CACHE[u] = self._review_url
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return self._review_url + self.projectname
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return self._review_url + self.projectname
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