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Use next(iterator) rather than iterator.next()
iterator.next() was replaced with iterator.__next__() in Python 3. Use next(iterator) instead which will select the correct method for returning the next item. Change-Id: I6d0c89c8b32e817e5897fe87332933dacf22027b
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@ -2321,8 +2321,8 @@ class Project(object):
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out = iter(out[:-1].split('\0')) # pylint: disable=W1401
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while out:
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try:
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info = out.next()
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path = out.next()
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info = next(out)
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path = next(out)
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except StopIteration:
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break
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@ -2348,7 +2348,7 @@ class Project(object):
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info = _Info(path, *info)
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if info.status in ('R', 'C'):
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info.src_path = info.path
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info.path = out.next()
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info.path = next(out)
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r[info.path] = info
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return r
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finally:
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@ -113,7 +113,7 @@ the following meanings:
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try:
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state = project.PrintWorkTreeStatus(output)
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if state == 'CLEAN':
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clean_counter.next()
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next(clean_counter)
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finally:
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sem.release()
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@ -141,7 +141,7 @@ the following meanings:
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for project in all_projects:
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state = project.PrintWorkTreeStatus()
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if state == 'CLEAN':
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counter.next()
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next(counter)
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else:
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sem = _threading.Semaphore(opt.jobs)
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threads_and_output = []
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@ -164,7 +164,7 @@ the following meanings:
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t.join()
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output.dump(sys.stdout)
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output.close()
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if len(all_projects) == counter.next():
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if len(all_projects) == next(counter):
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print('nothing to commit (working directory clean)')
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if opt.orphans:
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